2x^2+17x-10=20

Solution for 2x^2+17x-10=20 equation:

2x^2+17x-10=20

We move all terms to the left:

2x^2+17x-10-(20)=0

We add all the numbers together, and all the variables

2x^2+17x-30=0

a = 2; b = 17; c = -30;
Δ = b2-4ac
Δ = 172-4·2·(-30)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-23}{2*2}=\frac{-40}{4}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+23}{2*2}=\frac{6}{4}
=1+1/2
$